String inputString=”1.I am a code error resolver\n”+”2.Here I am resolving a regex exception\n”+”3.You need to keep in mind while using the regex or special characters in java\n”+”4.Some of the special symbols are reserved”;
will throw an Exception as ** is reserved in Java.
The exception thrown will be :
Exception in thread “main” java.util.regex.PatternSyntaxException: Dangling meta character ‘*’ near index 0 **
So use other characters or symbols other than * and $ as they are reserved and if used for string replacement will throw the dangling meta character Exception.